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kirill115 [55]
3 years ago
12

The table represents the linear function f(x), and the equation represents the linear function g(x). Compare the y-intercepts an

d slopes of the linear functions f(x) and g(x) and choose the answer that best describes them. x f(x) 0 1 2 9 4 17 g(x) = 3x + 1
Mathematics
2 answers:
-BARSIC- [3]3 years ago
6 0

Answer:

Its c

call me if you see this  

561-567-1015

Step-by-step explanation:

tatyana61 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

idk tbh

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Find the slope of the line y=1 over 6 x + 3 over 2
neonofarm [45]

Answer:

1/6x

Step-by-step explanation:

the slope intercept form is: y = mx + b

m = slope

b = y-intercept.

When you already have in the form the slope is where m is, so the number that's is with x. In this case it's 1/6x.

5 0
3 years ago
Solve for x: 3(x + 1) = -2(x - 1) - 4
shepuryov [24]

Answer:

x = -1

Step-by-step explanation:

3(x+1) = -2(x-1) - 4

3x + 3 = -2x + 2 - 4

3x + 3 = -2x - 2

Add the -2x to both sides

5x + 3 = -2

Subtract the 3 to both sides

5x = -5

Divide both sides by 5

x = -1

4 0
3 years ago
What percent df 160 is 56? Use the percent bar model.
Aleks [24]

Answer:

35%

i think

Step-by-step explanation:

6 0
3 years ago
6+5(4) please help ​
kaheart [24]

Answer:

26

Step-by-step explanation:

5 * 4 = 20

20 + 6 = 26

5 0
3 years ago
Read 2 more answers
Someone please help me
guapka [62]
Let the sides of the polygon (which is a triangle, by the way) be x, y and z.  The sum of x, y and z is the perimeter of the original poly, and this equals 18 cm.

Letting f be the scale factor,   f(18 cm) = 12 cm.  Then f=2/3.

The dilation reduces the size of the polygon by a factor of 1/3, producing a similar polygon which is 2/3 the size of the original one.

In each case we have 3 side lengths but no angles.  We can use Heron's formula to obtain the area in each case.  Look up Heron's formula.  In one version of this formula, p is half the actual perimeter, meaning that p is 18 cm / 2 for the first triangle and 12 cm / 2 for the second. 

The area of the first triangle would be

A18 = sqrt( 9(9-x)(9-y)(9-z) )

whereas 

A12 = sqrt( 6(6-x*a)(6-y*a)(6-z*a) ), where a represents the dilation factor 2/3.

Then the ratio of the areas of the 2 triangles is

sqrt( 6(6-x*a)(6-y*a)(6-z*a) )
---------------------------------------
  sqrt( 9(9-x)(9-y)(9-z) )

5 0
3 years ago
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