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Marizza181 [45]
3 years ago
9

Can u please help me on part C? The arcs in the photo at the right appear to be paths of stars rotating about the North Star. To

produce this effect, the photographer set a camera on a tripod and left the shutter open for an extended time. If the photographer left the shutter open for a full 24 hours, each arc would be a complete circle. You can model a star’s “rotation” in the coordinate plane. Place the North Star at the origin. Let P(1, 0) be the position of the star at the moment the camera’s shutter opens. Suppose the shutter is left open for 2 h 40 min, with the arc ending at P`. a. What angle of rotation maps P onto P`? b. What are the x- and y-coordinates of P` to the nearest thousandth? c. What translation rule maps P onto P`?
I have the other two questions answered but I included the rest for context. I only need C.
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

no i would if i could but sadly i dont know the answer.

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Show problem set up for full credit.
ICE Princess25 [194]

Answer:

∠ QPR = 125°

Step-by-step explanation:

the angles subtended by 2 congruent arcs are congruent , that is

5x = 4x + 25 ( subtract 4x from both sides )

x = 25

Then

∠ QPR = 4x + 25 = 4(25) + 25 = 100 + 25 = 125°

5 0
2 years ago
Bob saved $36.24.bill saved1/3 as much as bob how much did both boys save?
Rus_ich [418]
I believe they saved 48.32 together because $36.24 divided by 3 is $12.08 and $36.24 + $12.08 = $48.32
7 0
3 years ago
Read 2 more answers
Nancy started the year with $425 in the bank and is saving $25 each week. Sam started the year with $705 but is spending $15 a w
julia-pushkina [17]

Answer:

Step-by-step explanation:

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6 0
3 years ago
An experiment was conducted to observe the effect of an increase in temperature on the potency of an antibiotic. Three 1-ounce p
ludmilkaskok [199]

Answer:

a) y=-0.317 x +46.02

b) Figure attached

c) S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03

Step-by-step explanation:

We assume that th data is this one:

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

a) Find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324

\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900

And the slope would be:

m=-\frac{1900}{6000}=-0.317

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60

\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27

And we can find the intercept using this:

b=\bar y -m \bar x=27-(-0.317*60)=46.02

So the line would be given by:

y=-0.317 x +46.02

b) Plot the points and graph the line as a check on your calculations.

For this case we can use excel and we got the figure attached as the result.

c) Calculate S^2

In oder to calculate S^2 we need to calculate the MSE, or the mean square error. And is given by this formula:

MSE=\frac{SSE}{df_{E}}

The degred of freedom for the error are given by:

df_{E}=n-2=12-2=10

We can calculate:

S_{y}=\sum_{i=1}^n y^2_i -\frac{(\sum_{i=1}^n y_i)^2}{n}=9540-\frac{324^2}{12}=792

And now we can calculate the sum of squares for the regression given by:

SSR=\frac{S^2_{xy}}{S_{xx}}=\frac{(-1900)^2}{6000}=601.67

We have that SST= SSR+SSE, and then SSE=SST-SSR= 792-601.67=190.33[/tex]

So then :

S^2=\hat \sigma^2=MSE=\frac{190.33}{10}=19.03

5 0
3 years ago
3^3 . x^2- 25 divided by 5 when x= 0.6
Alenkasestr [34]

Hey there!

3^3 * x^2 - 25 / 5

= 3^3 * 0.6^2 - 25 / 5

= 3 * 3 * 3 * 0.6 * 0.6 - 25 / 5

= 9 * 3 * 0.6 * 0.6 - 25 / 5

= 27 * 0.36 - 25 / 5

= 9.72 - 25 / 5

= 9.72 - 5

= 4.72


Therefore, your answer is: 4.72


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

7 0
3 years ago
Read 2 more answers
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