2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j
Answer:
See attachment.
Step-by-step explanation:
See attachments.
Answer:
length=4 meters. width= 40 meters.
Step-by-step explanation:
88-4*2=80. 80 divided by 2 is 40. So, the width os 40 meters and the length is 4 meters.
100 : 8 = 12.5
12.5 Km per liter is your answer
0.129 is the change in the growth rate of company.
According to statement
we have to find and compare the growth rate of the company weekly.
we use the growth rate formula is
GROWTH RATE = present - past / present
Substitute the values in this formula
1st week = 220-190 / 220
1st week = 0.136
2nd week = 252-220 / 252
2nd week = 32 / 252
2nd week = 0.126
3rd week = 290-252 / 290
3rd week = 0.131
4th week = 337 - 290 / 337
4th week = 0.139
5th week = 380 - 337 / 380
5th week = 0.113
6th week = 440 - 380 / 440
6th week = 0.136
7th week = 505 - 440 / 505
7th week = 0.128
Now we find the average value of growth rate
Average = 0.136 + 0.126+0.131+0.139+0.113+0.136+0.128 /7
Average = 0.909/7
Average = 0.129
So, 0.129 is the change in the growth rate of company.
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