Find the area of the quadrilateral ABCD.
1 answer:
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Answer:
See below
Step-by-step explanation:
When you have 2 sides and the angle between them you use the cosine theorem or law of cosines:
After you have a side and the opposed angle (side b and angle B), you use the law of sines:
I will calculate angle A first:
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Same for angle C:
The sum of the angles is 36° + 61.2° + 25.3° = 122.5°; The sum must be 180° so this isnt a triangle.
I re did the problem using B as 63° instead of 36° in case you wrote it wrong and I got a satisfactory answer.
using B = 36:
b = 36.6
angle A = 86.4°
angle C = 29.1°
A+B+C = 86.4° + 29.1° + 63° = 178.5° ~ 180°
