Answer: q = 40
Step-by-step explanation:
Given the quadratic formula as
x = [-b +/-√(b^2 -4ac)]/2a
b = -14
a = 1
c = q
Difference d between the two roots.
d = [-b + √(b^2 -4ac)]/2a - [-b -√(b^2 -4ac)]/2a
d = 2√(b^2 -4ac)/2a
d = √(b^2 -4ac)/a
And d = 6
Substituting the values of a,b and c. We have;
6 = √[(-14^2) - (4×1×q)]
Square both sides
6^2 = 196 - 4q
4q = 196 - 36
q = 160/4
q = 40
The equation becomes
x^2 - 14x + 40 = 0
Hi There!
Change all the fractions to decimal you do that by dividing numerator by the denominator. Remember

as a decimal is 0.5
A=

= 0.43
B=

= 0.60
C=

= 0.8
D=

= 0.42
E=

= 0.6
Based, on the data above B,C,E are greater than

because they all have decimals greater than 0.5, B= 0.6, C= 0.8, E=0.6
So,

are all greater than

Hope This Helps :)
That is false... coefficients in polynomials can lead in either positive or negative
Answer:
Step-by-step explanation:
Divide the tens column dividend by the divisor.
Multiply the divisor by the quotient in the tens place column.
Subtract the product from the divisor.
Bring down the dividend in the ones column and repeat.
okay so look at the image down below