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aev [14]
4 years ago
9

In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers

Mathematics
2 answers:
ElenaW [278]4 years ago
7 0
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number":  "i" ;  which represents the "imaginary number" ;  " √-1 " .

Since:  "i = √-1" ; 

Note that:   " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
__________________________________________________
Gnesinka [82]4 years ago
6 0
Hello human, potato or other species,

The answer you are looking for is.....


Yes!


Hope i helped

Have a great day!
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NemiM [27]

Answer:

55,98,27

Step-by-step explanation:

To solve for the angles we must first find y with this equation

3y+5+2y-7=153

We can simplify this

5y-2=153

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155/5=31

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We now know y and can plug it into the angles

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<B=98

Now time for the last angle

Since angle BCA and DCB are next to each other they add up to 180

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3 years ago
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
Semenov [28]

Answer:

9.4 secs

Step-by-step explanation:

From Newton's law of cooling;

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137 - 60 = 125 e^-(0.0518t)

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ln [e^-(0.0518t)] = ln(77/125)

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3 years ago
What is the domain of the function {(-1,1) (0,0) (1,2)}
kipiarov [429]
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3 years ago
427 thousand in scientists notation
Masja [62]

Answer:

4.27 x 10^5

Step-by-step explanation:

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8 0
3 years ago
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aev [14]

Answer:

132 degrees

Step-by-step explanation:

its the same as the other side since its a rhombus :)

did i help?

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