Answer:no
the answer is c
Step-by-step explanation:
HD = 10.5
Step-by-step explanation:
Given BH = 3, GH = 2, BF = 10
Step 1: To find HF:
HF = BF – BH
HF = 10 – 3
HF = 7
Step 2: To find HD:
We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.
⇒ GH × HD = BH × HF
⇒ 2 × HD = 3 × 7
⇒ HD = 10.5
Hence, the value of HD = 10.5.
Answer:
B
Step-by-step explanation:
All we have to do is plug in the values! 1/2(4)(10+5) will give us the area. Now we simplify!
2(15) = A
30=A
Our answer is B!
Answer:
Please check the explanation.
Step-by-step explanation:
The midpoint (a, b) of line joining points (x₁, y₁) and (x₂, y₂)
a = x₁ + x₂ / 2
b = y₁ + y₂ / 2
Given that the midpoint of AB is (4, -3).
i.e. (a, b) = (4, -3)
Given that A has coordinate (1, 5).
i.e. (x₁, y₁) = (1, 5)
We have to determine the coordinates of B.
i.e. (x₂, y₂) = B
Thus,
4 = (1 + x₂)/2
(1 + x₂) = 4 × 2
1 + x₂ = 8
x₂ = 7
and
-3 = (5 + y₂)/2
(5 + y₂) = -3 × 2
5 + y₂ = -6
y₂ = -11
so (x₂, y₂) = (7, -3) = B
Thus, the coordinates of B = (x₂, y₂) = (7, -3)
Therefore,
x₂ + y₂ = 7 + (-3)
= 7 - 3
= 4
Hence, the value of x₂ + y₂ = 4
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>