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ohaa [14]
3 years ago
8

Edhesive Intro to CS: 3.4 Code Practice: Question 1, Input a word. If it is "yellow," print "Correct." Otherwise, print "Nope."

What happens if you type in "YELLOW" or "YellOW?" Does the capitalizing make a difference?
Computers and Technology
2 answers:
Brilliant_brown [7]3 years ago
6 0

Answer:

p

Explanation:

Novosadov [1.4K]3 years ago
4 0

Answer:

yes it does

Explanation:

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Do you want me the money for the policy that has been canceled

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3 years ago
31. Explain what the program does. Write out the output 20 PRINT "Hellooo00000000000, world!" 30 PRINT "I'm learning about comma
inna [77]

o_num = input ("Please enter the amount of \"o\": ")

zero_num = input ("Please enter the amount of zeros: ")

i = 0

while i < o_num and i < zero_num:

repeat_o = "Hell" + o_num

repeat_zero = repeat_o + zero_num

i+=1

print (repeat_zero)

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Name the three basic storage device of a computer​
grigory [225]
Hard disk Drive, random access memory, USB flash memory
7 0
3 years ago
Read 2 more answers
You do not need to use any functions beyond the main function in this problem. Initialize an array of int with the values: 4, 6,
zheka24 [161]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    int[] arr = {4, 6, 9, 12};

    int sum = 0;

   

    for(int i=0; i<arr.length; i++){

        sum += arr[i];

    }

   

    for(int i=0; i<arr.length; i++){

        System.out.print(arr[i] + " ");

    }

    System.out.println("");

 System.out.println("The sum of the numbers: " + sum);

}

}

Explanation:

* The code is written in Java.

- Initialize the array with the given numbers

- Initialize the <em>sum</em> variable as zero

- Calculate the sum in the first for loop

- Print the numbers in the second for loop

- Print the <em>sum</em>

4 0
3 years ago
Why are new versions of applications packages released often ​
stellarik [79]

Answer:

The answer is "new version of application provides more easy to use".

Explanation:

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  • The update usually improves the device or service in its current version, whilst an improvement is an entirely new version. Installation is usually free and easy. You also have to wait for updates that are difficult to install.
5 0
3 years ago
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