Answer:
The correct selection is the letter C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router.
Explanation:
In this case, the letter C is the right answer because with the first ACL exactly:
access-list 102 deny tcp any any
We are denying all traffic with the next line deny tcp any any, in this case, the others line are being ignored.
access-list 104 permit udp host 10.0.0.3 any
access-list 110 permit tcp host 10.0.0.2 eq www any
access-list 108 permit tcp any eq ftp any
For that nobody can access to the internet, the security administrator of ABC must change the first ACL.
False it is false people also hand draw stuff
Answer:
import java.util.Scanner;
public class Solution {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter your value");
int value = scan.nextInt();
greaterThanFive(value);
}
public static void greaterThanFive(int userInput){
System.out.println(userInput > 5);
}
}
Explanation:
The first line import the Scanner which is use to enable to accept user input.
The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.
Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.
The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).
