Ask question

Ask question

All categories

Mandarinka [93]

2 years ago

7

What is the distributive property of 8(y-7)=-16

2 answers:

Sunny_sXe [5.5K]2 years ago

8 0

Answer:

y=5

Step-by-step explanation:

8(y-7)= -16

(8)y-(8)7= -16

8y-56= -16

-16+56= 40

40/8= 5

y=5

(when you get y by itself)

hoped this helped a little bit.

Alex_Xolod [135]2 years ago

4 0

Step-by-step explanation:

$\text{The distributive property:}\\\\a(b-c)=ab-ac\\\\8(y-7)=(8)(y)-(8)(7)=8y-56\\\\\text{If you want whole solution:}\\\\8(y-7)=-16\\8y-56=-16\qquad\text{add 56 to both sides}\\8y-56+56=-16+56\\8y=40\qquad\text{divide both sides by 8}\\\dfrac{8y}{8}=\dfrac{40}{8}\\\boxed{y=5}$

You might be interested in

Plsss helpppp 6x^2+4x-42

melisa1 [442]

Answer:

Step-by-step explanation:

6x^2+4x-42

2(3x^2+2x-21)=0

3x^2+2x-21=0

3x^2+(9-7)x-21=0

3x^2+9x-7x-21=0

3x(X+3)-7(X+3)=0

(3X-7)(X+3)=0

So Answer is (3x-7)(X+3)

6 0

2 years ago

How do you write 16 tens

Rzqust [24]

16 tens = 16 x 10 = 160 ones

4 0

2 years ago

Read 2 more answers

Question 1 (1 point)

dimulka [17.4K]

Answer: ik 2/3 Ian one but don’t know about the others

8 0

2 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

2 years ago

what is the volume of the hamsta snack box with a width of 1 1/2 inches, a length of2 1/2 inches, and a height of 4 inches

jenyasd209 [6]

<u>Given:</u>

The width of the snack box is $1 \frac{1}{2} \ inches=\frac{3}{2} \ inches$

The length of the snack box is $2 \frac{1}{2} \ inches=\frac{5}{2} \ inches$

The height of the snack box is 4 inches.

We need to determine the volume of the hamsta snack box.

<u>Volume of the box:</u>

The volume of the box can be determined using the formula,

$V=L \times W \times H$

where L is the length, W is the width and H is the height of the box.

Substituting the values, we get;

$V=4 \times \frac{3}{2} \times \frac{5}{2}$

Simplifying, we get,

$V=\frac{60}{4}$

$V=15 \ in^3$

Thus, the volume of the Hamsta snack box is 15 cubic inches.

3 0

2 years ago