If the first roll is a three, then the only chance of the sum of the two numbers being less than six is if you roll a 1 or a 2.
That is 2/6 chance, or simplified, a 1/3 chance.
I hope this Helps!
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
Greetings from Brasil...
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Here's our problem:
From potentiation properties:
Mᵃ ÷ Mᵇ = Mᵃ⁻ᵇ
<em>division of power of the same base: I repeat the base and subtract the exponents</em>
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Bringing to our problem
12¹⁶ ÷ 12⁴
12¹⁶⁻⁴
<h2>12¹²</h2>
Lets just use
for an example. If the number is increased by 60% and the denominator is decreased by 20% we get the new fraction being:
. Since then new one is equal to 1, and the original is equal to
, we see that this manipulation of the fraction causes an increase of 100%.
Answer:
A
Step-by-step explanation:
here's how I got it A and C are similar but C will have a different answer because you will multiply 12*7 then add 91 that will equal 175 but it wants the answer that is 12 larger than 7 + 91. when it is in parenthesis it goes first so then you do 7+91 first and that is 98. then multiply 12*98=1176 and that is the correct answer because it is 12 times the sum of 7 and 91.
