Eight less than one half a number is two

Solve for x. Show your work.<br><br> - x < -12

timama [110]

$- x \ \textless \ -12\\x\ \textgreater \ 12$

8 0

3 years ago

A golfers score after playing on friday was +2

jek_recluse [69]

The end of his round on Saturday was a -5, and the end of his round on Sunday was a 0.

6 0

3 years ago

Need this ASAP please help!#2

myrzilka [38]

Answer:

The correct option is 3.

Step-by-step explanation:

From the given graph it is noticed that the related line passing through the point (-3,1) and (0,3).

If a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of related line is

$y-1=\frac{3-1}{0-(-3)}(x-(-3))$

$y-1=\frac{2}{3}(x+3)$

$y-1=\frac{2}{3}(x)+2$

Add 1 on both the sides.

$y=\frac{2}{3}(x)+2+1$

$y=\frac{2}{3}(x)+3$

The equation of related line is $y=\frac{2}{3}(x)+3$ .

The related line is a dotted line, it means the point on the line does not included in the solution set.

The shaded region is above the line so the sign of inequity is >.

The required inequality is

$y>\frac{2}{3}(x)+3$

Therefore option 3 is correct.

6 0

3 years ago

13(6x – 5) – x = 13 – 2(x + 1)

Murrr4er [49]

Answer:

x = 76/79

Hope this helped

7 0

3 years ago

Read 2 more answers

URGENT! 40 POINTS! PLEASE HELP!

umka2103 [35]

Answer:

(a) $8 x(5 x-6)=40 x^{2}-48 x$

(c) $\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}$

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation $8 x(5 x-6)$

$8 x(5 x-6)=40 x^{2}-48 x$

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation $-4 x\left(2 x^{2}+1\right)$

$-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x$

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation $(x-3)(5 x-6)$

$\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}$

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation $(2 x+3)\left(x^{2}+3 x-5\right)$

$\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}$

Hence, the given statement is false.

4 0

3 years ago

Read 2 more answers