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3 years ago

For the data in the table, tell whether y varies directly with x. If it does, write an equation for the direct variation.

Mathematics

1 answer:

allochka39001 [22]3 years ago

4 0

It is direct variation if x/y is a constant.

x/y = 2 / -6.6 = -1/3.3

y/x = -9.9/3 = -3.3

y/x = -6.6/ 2 = -3.3

y/x = -13.2/ 3 = -3.3

y/x = -16.2/ 3 = -3.24

So its not exactly direct variation as the last values is slightly different from the first 3.

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John has 13 boxes of apples. Each box holds 6 apples. If 7 of the boxes are full, and 6 of the boxes are half full, how many app

TEA [102]

John would have 60 apples!
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3 years ago

When the stranger came into the forest, 37 percent of the people ran to hide. If 2520 refused to hide, how many people lived in

STALIN [3.7K]

Is 37% Ran to hide then 63% refuse to hide

63/2520= 37/X
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3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

Math question please help urgently

djverab [1.8K]

Answer:

0, negative 9 and your welcome

6 0

3 years ago

Please help if you can!

meriva

Answer:

(0 ; -3)

Step-by-step explanation:

The y-intercept is where the line touches the y axis meaning that x is 0.

4 0

2 years ago

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