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Rus_ich [418]
3 years ago
10

What is the unit rate??

Mathematics
1 answer:
telo118 [61]3 years ago
6 0
The unit rate is 5.5
Equation: 11 divided by 2=5.5
Unit rate is how much it is for just one object
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Find the area enclosed by the curve y^2=x^2-x^4
yulyashka [42]

Answer: 4/3

Step-by-step explanation:

As you know this graph is a lemniscate

4\int\limits^1_0 {x\sqrt{1-x^{2} } \, dx =\frac{4}{3} =1.33$

4 0
3 years ago
Pls help tap picture to see the three problems
valentinak56 [21]
1. Slope intercept form. First find two points to get slope: (0,-3) and (-3,-4). Slope is
(-4 - -3)/(-3 - 0)= 1/3
Use one of the points of (x,y) to solve for b
Y=1/3x + b
-3 = 1/3(0) + b
-3 = b so your slope intercept equation is
Y = 1/3x - 3

2. Rate of Change is slope. Your points are (0,10) and (24,6) so slope is (6-10)/(24-0)
= - 1/6 which means that for each 1 unit increase in x, y decreases by 1/6.

3. Standard form is ax + by =c
Notice it is the same line as in the first graph so it's the same equation
y = 1/3x - 3
First, you cannot have fractions, so you have to multiply the equation by 3 to get rid of the 1/3.
3y= x - 9. Now move the x over:
-x + 3y = - 9. Now get rid of the negative value on x by multiplying the entire equation by -1:
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8 0
3 years ago
You know that the battery in your alarm clock is going to run out of power soon. If it runs out within the next 24 hours, what i
aivan3 [116]
The probability of an event is given by the number of favorable outcomes divided by the total number of outcomes. Here the event is the alarm clock running out of power. There are 24 hours during which the power can go out. You are asleep during 8 of these. A "favorable" outcome in this case is the power going out while you are sleeping -- that is, during one of those 8 hours. This makes the probability that the power goes out while you are sleeping 8/24.
3 0
3 years ago
a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.​
Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = <u>6.15</u><u> </u><u>N</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>effort</u><u> </u><u>applied</u><u> </u><u>=</u><u> </u><u>6.15</u><u> </u><u>N</u>

<u>Hope</u><u> </u><u>this</u><u> </u><u>answer</u><u> </u><u>helped</u><u> </u><u>you</u><u>.</u><u>.</u>

<u>Please</u><u> </u><u>mark</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>brainliest</u><u> </u>

8 0
9 months ago
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