A line can be formed by at least two known data points. When these two are given, you can connect them and extend infinitely in one direction for both ends. So, that is how we're going to approach the problem. The two points that can be easily determined are the x- and y-intercepts. These are the points which the line intersects on the x- and y-axis, respectively. If we want to find for the x-intercept, just let y=0 and substitute it to the linear equation. Then, we can solve for x. The same thing is done to calculate for the y-intercept.
Solving for the x-intercept: let y=0
-3x + 5y = 6
-3x + 0 = 6
-3x = 6
x = 6/-3
x = -2
Solving for the y-intercept: let x=0
-3x + 5y = 6
-3(0) + 5y = 6
5y = 6
y = 6/5
y = 1.2
So, the two points are (-2,0) and (0,1.2). The line drawn is shown in the picture. This is the graph of the linear equation given.
(3x+20)+(8x-16)=180
Combine like terms:
11x+4=180
Then solve
11x=176
X=16
X+2y=-7..... (1)
y=-6.....(2)
equation (2) into equation (1)
x+2y=-7
x+2(-6)=-7
x-12=-7
x=-7+12
x=5
Basically, you are asking how many ways can 5 objects be chosen from 12 (the order is NOT important).
The formula for this is n! / [ r! * (n-r)! ]
12! / [5! * 7!] =
12*11*10*9*8*7! / (5! * 7!) =
12*11*10*9*8 / 5 * 4 * 3 * 2 =
11*9*8 =
792 different collections
Source:
http://www.1728.org/combinat.htm
Answer:
25 hits
Step-by-step explanation:
The proportion of hits he makes to the total number of hits is 5:7. We can use the fact that seven times five is 35. If we multiply seven by five, we need to also multiply five by five to make the proportions equal. five times five is twenty five. And we're assuming he has the same number of hits every seven times.