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3 years ago

Out of 12 books, you plan to take 5 with you. how many different collections of 5 books can you take?

1 answer:

8 0

Basically, you are asking how many ways can 5 objects be chosen from 12 (the order is NOT important).
The formula for this is n! / [ r! * (n-r)! ]
12! / [5! * 7!] =
12*11*10*9*8*7! / (5! * 7!) =
12*11*10*9*8 / 5 * 4 * 3 * 2 =
11*9*8 =
792 different collections

Source:
http://www.1728.org/combinat.htm

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What angle relationship describes VQR and QRW?

Vlad [161]

Answer: alternate interior angles

Step-by-step explanation:

Got it Right on the test. :)

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3 years ago

There are 3 balls in a hat; one with the number 1 on it, one with the number 6 on it, and one with the number 7 on it. You

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Answer:

coin: ball:

head -- 6

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3 years ago

WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION PLS ANSWER THIS TRIGONOMETRY QUESTION

mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

$\theta=?$

Relationship between opposite and adjacent is given by tan angle

$Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}$

$Tan \theta=\frac{3}{4}$

$\theta=Tan^{-1}\frac{3}{4}$

$\bold{\theta=36.8°}$

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

$\theta=62°$

Relationship between height and hypotenuse is given by Sin angle

Sin 62°= $\frac{opposite}{hypotenuse}=\frac{b}{11}$

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At 9.71 cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°= $\frac{base}{hypotenuse}=\frac{a}{11}$

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is 5.16cm.

4 0

3 years ago

It has been said that newspapers are disappearing, replaced by various electronic media. In 2004, newspaper circulation (the num

shutvik [7]

Answer:

A. $y=-1.2x+59$

B. 42.2 million

Step-by-step explanation:

Part A:

Given:

Newspapers circulated in year 2004, $y_{1}=59\textrm{ million}$

Newspapers circulated in year 2014, $y_{2}=47\textrm{ million}$

Let the time $x$ start at the year 2004. So, $x_{1}=0$

For the year 2014, $x_{2}=2014-2004=10$

Therefore, linear relationship between newspapers circulated and time passed since 2004 is given as:

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\\y-59=\frac{47-59}{10-0}(x-0)\\y-59=-\frac{12}{10}x\\y=-1.2x+59$

Therefore, the equation describing the relationship is: $y=-1.2x+59$

Part B:

For the year 2018, $x=2018-2004=14$

Plug in 14 for $x$ in the above equation and solve for $y$ . This gives,

$y=-1.2(14)+59\\y=-16.8+59\\y=42.2$

Therefore, in the year 2018, the newspaper circulation will be 42.2 million.

8 0

3 years ago

Is this answer right?? If not what’s the real answer? I’m trying to practice for my STAAR.

Ierofanga [76]

Area of rectangle

21m^2

Area of one triangle

divide length of 7 by 2 (3.5)

gives you length b (unknown side that is not hypotenuse)

then multiply by width of triangle (4)

3.5 * 4 = 14

and in this situation there is no need to divide by two, because you essentially have one full square from both the triangles. this only works when both triangles are the same.

add the area of the rectangle

14+21= 35

35m^2

8 0

3 years ago