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Rashid [163]
3 years ago
9

Which expressions are equivalent to 5(-2k-3)+2k

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

-8k - 15

Step-by-step explanation:

5(-2k-3)+2k

At first, we will break the parenthesis. To break that, we will multiply the value inside the parenthesis by the adjacent number, that is 5. Again, we have to consider the Algebraic operation (Golden rule) -

[(-) x (-) = (+); (+) x (-) = (-)]

Therefore, since there is a minus sign in each of the value inside the parenthesis, the result will be minus as 5 is a positive integer.

or, -5*(2k) - (5*3) + 2k

or, -10k - 15 + 2k

or, -8k - 15 (after the deduction)

The answer is = -8k - 15

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4a + (–6b) – 3a + 2b factor the expression
Gemiola [76]

Answer:

a−4b

Step-by-step explanation:

Combine Like Terms:

=4a+−6b+−3a+2b

=(4a+−3a)+(−6b+2b)

=a+−4b

have a great day

5 0
3 years ago
suppose you know that over the last 10 years, the porbabiliy that your town would have at least one ma jor stor was 40%. describ
Anuta_ua [19.1K]

Answer:

The probability of a big storm is 40%.

Now, you can find a D10 (a die with 10 faces)

You can assign 4 numbers (0, 1, 2, 3) to the event "there is a major storm"

in this way, you have 40% of having a storm.

and the other 6 numbers (4, 5, 6, 7, 8, 9) to the event "there is not a major storm". This means that we have 60% of not having a storm.

now, when you roll the dice you can see if a year there will be a storm or not.

Now, you roll the dice 5 times (for the 5 years) and take note of the results and the number of storms in those 5 rolls.

Now do the same thing a bunch of times, at least 25 times.

Now, you recorded the results in each set of rolls, now see the number of sets that have at least years with storms.

Take that number and divide it by the total number of sets of data (in this case 25, for example)

The result is the probability that we are looking for.

6 0
3 years ago
What is the common ratio for this geometric sequence 27,9,3,1<br>A.1/6<br>B.6<br>C.3<br>D.1/3
iris [78.8K]
It will be D!!!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
Read 2 more answers
Write the number of measures (sides/angles/diagonals) needed to construct the following :
gladu [14]
  • Square <em>:</em><em>4</em><em> </em><em>sides</em><em>,</em><em>each</em><em> </em><em>side</em><em> </em><em>9</em><em>0</em><em> </em><em>degrees</em><em> </em><em>.</em><em>.</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>:each angle is 90 degrees

: 4 diagonals

  • Rectangle: 4 sides..4 angles..2 diagonals..
  • Rhombus : <u>4</u><u> </u><u>sides</u><u>.</u><u>.</u><u>2</u><u> </u><u>angles</u><u>.</u><u>.</u><u>.</u><u>2</u><u> </u><u>diagonals</u><u>.</u><u>.</u>
  • Parallelogram : 4 sides..4 angles..2 diagonals..
  • Quadrilateral: 4 sides...4 angles...4 diagonals..

<em>If</em><em> </em><em>this</em><em> answer</em><em> helps</em><em><u> you</u></em><em><u> plz</u></em><em><u> mark</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
Help me please! And quick! It's 7th grade level math...
Mademuasel [1]

Answer:

Number 5 is 10 pencils left in total(5 red, 5 blue) with 50 percent probability of getting red or blue. Number 6 is 9 left total (4 red, 5 blue) with a 44 percent probability of choosing a red one, 56 percent probability of choosing a blue one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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