The answer is Big Mac size
Mitosis is conventionally divided into 5 phases, which include prophase, prometaphase, metaphase, anaphase and telophase and cytokinesis.
Interphase
Before coming into mitosis, a mobile spends a length of its increase underneath interphase.
Prophase
Prophase straight away follows the S and G2 levels of the cycle and is marked by way of condensation of the genetic fabric to form compact mitotic chromosomes composed of chromatids attached at the centromere.
Prometaphase
In the prometaphase, the nuclear envelop disintegrates. Now the microtubules are allowed to extend from the centromere to the chromosome.
Metaphase
At this level, the microtubules start pulling the chromosomes with equal pressure and the chromosome ends up in the center of the cell. This area is referred to as the metaphase plate.
Anaphase
The splitting of the sister chromatids marks the onset of anaphase. These sister chromatids end up the chromosome of the daughter nuclei.
Telophase
The chromosomes that cluster at the two poles start coalescing into an undifferentiated mass, because the nuclear envelope begins forming round it.
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brainly.com/question/8757261
V1/T1=V2/T2
(15.5)/(360K)=(3.6)/(T2)
T2=83.61290K
T2=-189.3871 degrees Celsius
Tin and Aluminum are not considered as semiconductors but rather conductors themselves because they are metals. <span>Semiconductors are in general elements from column IV or or compounds of columns III and V of the periodic table.</span>
Germanium and silicon are semiconductors because they are metalloids.
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Answer:</h3>
6AgI + Fe₂(CO₃)3 → 2FeI₃+ 3Ag₂CO₃
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Explanation:</h3>
- The process of balancing chemical equations involves putting coefficients on reactants and products to ensure the number of atoms of each element is equal on both sides of the equation.
- It is a try and error method that is done to make an equation obey the law of conservation of mass.
In this case;
- Our unbalanced equation is, AgI + Fe₂(CO₃)3 → FeI₃+ Ag₂CO₃
- It can be balanced by putting the coefficients 6, 1, 2, 3.
- Therefore, the balanced chemical equation is;
6AgI + Fe₂(CO₃)3 → 2FeI₃+ 3Ag₂CO₃
