Answer:
We need 4.28 grams of sodium formate
Explanation:
<u>Step 1:</u> Data given
MW of sodium formate = 68.01 g/mol
Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L
pH = 3.74
Ka = 0.00018
<u>Step 2:</u> Calculate [base)
3.74 = -log(0.00018) + log [base]/[acid]
0 = log [base]/[acid]
0 = log [base] / 0.42
10^0 = 1 = [base]/0.42 M
[base] = 0.42 M
<u>Step 3:</u> Calculate moles of sodium formate:
Moles sodium formate = molarity * volume
Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles
<u>Step 4:</u> Calculate mass of sodium formate:
Mass sodium formate = moles sodium formate * Molar mass sodium formate
Mass sodium formate = 0.063 mol * 68.01 g/mol
Mass sodium formate = 4.28 grams
We need 4.28 grams of sodium formate
Answer:
Please find the definition and further explanation below
Explanation:
Based on the ability for the solvent (liquid substance) to dissolve a solute (solid substance), a solution can either be unsaturated, saturated or supersaturated. A SATURATED SOLUTION is that which contains the maximum amount of solute a solvent can possibly dissolve.
In other words, a saturated solution can no longer dissolve anymore solute, and hence, any further solute added forms crystals or makes the solution supersaturated.
Moles = weight in grams / molecular weight.
So I would divide the "grams of barium" by its molecular weight (which is 137.3) to get "moles of barium". :)
