When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.
<h3>What is a precipitate?</h3>
The precipitate is the solid concentration of a substance that is collected over a solution.
First, we determine the concentration of magnesium and hydroxide
(Mg2+) = 7.00 × 10⁻⁴
(OH−) = 5.00 × 10⁻⁵
Now, we calculate the solubility quotient
Qc = (Mg2+) (OH−) ²
Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²
Qc = 1.75 x 10⁻¹²
The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.
Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.
To learn more about precipitate, refer to the below link:
brainly.com/question/16950193
#SPJ4
Diameter = 200pm
200pm -> mm
200pm *^-12 / 1*10^-3 = .0000002
2.0*10-7x mm = 1.0mm
Divide x on both sides
Explanation:
divide the weight in grams by the atomic mass from the periodic table, then multiply the result by Avogadro's number..
Hope this works!!
Answer:
P = 83.16 Watt
Explanation:
Given data:
Mass of box = 2 Kg
velocity of box = 29.7 m/s
Time = 21 sec
Power = ?
Solution:
Formula:
Power = work done/time
Now we will calculate the work done.
W = force × distance ...... (1)
d = speed /time
d = 29.7 m/s× 21 s
d = 623.7 m
Force:
acceleration = 29.7 m/s / 21 s
a = 1.4 m/s²
Force = m×a
Force = 2 kg×1.4 m/s²
Force = 2.8 N
Now we will put the values in equation 1.
W = F × d
W = 2.8 N ×623.7 m
W = 1746.36 Nm
Now for power:
P = W / time
P = 1746 Nm / 21 s
P = 83.16 Watt
Answer:
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Explanation:
Step 1: Data given
Moles ethane produced = 13.78 moles
Step 2: The balanced equation
C2H2 + 2H2 → C2H6
Step 3: Calculate moles of hydrogen
For 1 mol acetylene (C2H2) we need 2 moles hydrogen (H2) to produce 1 mol of ethane (C2H6)
For 13.78 moles ethane produced we need 2*13.78 = 27.56 moles hydrogen (H2)
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)