1. y = 2/3x - 5
2. 4x - 6y = 30
Divide 2. by 2
3. 2x - 3y = 15
Substitute 1. into 3.
4. 2x - 3(2/3x - 5) = 15
5. 2x - 2x + 15 = 15
6. 15 = 15
False. There are an infinite number of solutions.
6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
The answer is 2x^3
Because there are two of the same squares and the volume of a square is x^3
The correct equation is the last one, where secx =hypotenuse ÷ adjacent, secx is the inverse of cosx, and if you recall, cosx=adjacent÷hypotenuse