Math question please help me

GEOMETRY: You are building a shelf that fits in a corner. In the figure, the entire shelf is IJK . Each unit in the coordinate p

arsen [322]

Answer:

A= 12.5 inches²

Step-by-step explanation:

a=1/2bh

a=1/2(5)5

a=1/2(25)

a= 12.5

3 0

2 years ago

Ramon earns $1,735 each month and pays $53.10 on electricity. To the nearest tenth of a percent, what perfect of ramons earnings

Alenkinab [10]

Answer:

$\boxed{3.1 \, \%}$

Step-by-step explanation:

The formula for calculating percentage is

$\text{Percentage} = \dfrac{\text{Part}}{\text{Whole}} \times 100 \, \%$

The "part" is the electricity payment.

The "whole" is Ramon's earnings.

$\begin{array}{rcl}\text{\% of earnings} & = & \dfrac{53.10}{1735} \times 100 \, \% \\\\& = & \mathbf{3.1 \, \%}\\\end{array}\\\boxed{\mathbf{3.1 \, \%}} \text{ of Ramon's earnings are on electricity}$

5 0

2 years ago

Given X = {15, 22, 33, 44, 89, 165, 1025} and Y = {-5, 15, 33, 88, 99, 150, 160, 1025}, which of the following statements is fal

vitfil [10]

Answer:

the first one

Step-by-step explanation:

in the first one it says there are no common numbers between x and y which is false.

in the second one its the union of x and y which means that you must list all numbers in x and y without repetition

the third one states that 15,33,1025 are the only numbers that are common between x and y.

so as a breif the first one is wrong

5 0

2 years ago

Of interest is to determine the mean age of students at the time they take the comprehensive exam for all students enrolled in g

Gnoma [55]

Answer:

The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 31 - 1 = 30

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 2.457

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.457\frac{2.9}{\sqrt{31}} = 1.3$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 27.5 - 1.3 = 26.2 years

The upper end of the interval is the sample mean added to M. So it is 27.5 + 1.3 = 28.8 years

The 98% confidence interval for the mean age of students at the time they take the comprehensive exam for all students enrolled in graduate programs that require students to take comprehensive exams is between 26.2 and 28.8 years. This means that we are 98% sure that the mean age of all students taking the exam is between 26.2 and 28.8 years.

8 0

2 years ago

A stick l feet long broken into two parts, one of which is twice as long as the other. How long is the shorter piece? Use algebr

Sergio [31]

Answer:

the shorter piece is L ÷ 3 feet long in the case when the original stick is L feet long

Step-by-step explanation:

It is given that

The stick is L feet long

And, the two pieces are x and y

Now according to the question

It is given that

one of which is twice as long as the other

so,

x = 2y

x + y = L

Put the value of x in the above equation

So,

2y + y = L

3y = L

Now divide by 3

y = L ÷ 3

Hence, the shorter piece is L ÷ 3 feet long in the case when the original stick is L feet long

6 0

2 years ago