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vichka [17]
3 years ago
9

The value of x + y is negative, and x is a positive integer. What must be true about y? Explain.

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

Y must be negative

Step-by-step explanation:

Use this equation as an example: 5 + -7 = negative

If you add both of them you end up with -2

-2 is a negative integer

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Rashawn and Jessie are playing a game where they lose the same number of points that they would have earned for each incorrect a
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Which phrase describes the variable expression y - 12
ahrayia [7]

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Read 2 more answers
Lexi can paint 5 yards of fencing in one hour. At this rate how many inches does she paint per min?
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7 0
4 years ago
F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x
olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

4 0
3 years ago
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