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makkiz [27]
2 years ago
11

Can someone graph x < 2?

Mathematics
1 answer:
natima [27]2 years ago
5 0
This would be the graph

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The function
maks197457 [2]

Answer: What??????

Step-by-step explanation:

im ll years old

8 0
2 years ago
Write an equation in slope-intercept form for the line that passes through (2,-2) and is perpendicular to x + 5y =6
Oksana_A [137]
X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1....and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.

y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b

so ur perpendicular equation is : y = 5x - 12 <=
3 0
3 years ago
25 pt question amd will mark brainliest
Usimov [2.4K]
Hello!

The angles are supplementary meaning they add to 180°

a + 2a + 3 = 180

Combine like terms

3a + 3 =  180

Subtract 3 from both sides

3a = 177

Divide both sides by 3

a = 59

the answer is 59°

Hope this helps!
8 0
2 years ago
Read 2 more answers
Find IIaII given a=(3,-7)
EastWind [94]
||a|| is called the norm of a. The answer is square root of 58. Hope it helps

4 0
3 years ago
A third-degree polynomial function f has real zeros -2, ½, and 3, and its leading coefficient negative. Write an equation for f.
Rom4ik [11]
F(x) = k(x+2)(2x-1)(x-3), where k is some constant
= k(2x^3-3x^2-11x+6)
= k(-2x^3+3x^2+11x-6)

k defines some vertical stretch, so there are an infinitely many solutions for f(x).
8 0
3 years ago
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