Ask question

Ask question

All categories

borishaifa [10]

3 years ago

12

Officer Brimberry wrote 16 tickets for traffic violations last week, but only 2 tickets this week. What is the percent decrease?

Give your answer to the nearest tenth of a percent.

1 answer:

Verdich [7]3 years ago

6 0

Answer:

87.5%

Step-by-step explanation:

It decreased by 16 - 2 or 14, and since he wrote 16 tickets last week, the answer is 14/16 in percent form, or 7/8 = 87.5%.

You might be interested in

The length of the sides of a rectangle are 60 and 91 centimeters. The is the length of the diagonal?

Elena L [17]

use Pythagoras

D=

$d = \sqrt{60 { }^{2} } + 91 {}^{2}$

Diagonal =109 cm

3 0

3 years ago

Read 2 more answers

Help meeee i need 100

zubka84 [21]

Jay’s elevation is at -20.
Talia’s elevation is at 20.

8 0

2 years ago

Re-write the quadratic function below in Standard Form<br> y=5(x + 1)^2+9

omeli [17]

Answer:

y = 5x^2+10x +14

Step-by-step explanation:

y = 5(x+1)^2+9

= 5(x^2+2x+1)+9

= 5x^2+10x +14

4 0

3 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

3 years ago

Find the inverse of f(x)=1/(x^3)

Pepsi [2]

Answer:

Step-by-step explanation:

y $f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}$

4 0

3 years ago