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3 years ago

How many positive integer factors of 100! are multiples of 2 or 3?

Mathematics

1 answer:

elena-s [515]3 years ago

3 0

Positive integer factors of 100:

1, 2, 4, 5, 10, 20, 25, 50, 100

Now find if they are a multiple of 2 or 3.

2, 4, 10, 20, 50, 100

That is 6 factors.

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Half of a number decreased by 27

bija089 [108]

"Half of a number decreased by 27" can be displayed as:

1/2x - 27

3 0

3 years ago

Let u = <-3, -5>, v = <-3, 1>. Find u + v. <-2, -8> <-8, -2> <0, -6> <-6, -4>

salantis [7]

Answer:

<-6,-4>

Step-by-step explanation:

To find u+v, all you have to do is add the corresponding components of each.

That is for example on this problem, you would do

<-3,-5>+<-3,1>

=<-3+-3,-5+1>

=<-6,-4>.

7 0

3 years ago

How to algebraically find the limit of a function as x approaches infinity?

Sauron [17]

Well... One way you can do this is by testing a set of arrays and see the trend. If I chose to find what y1 is in (100, y1) and what y2 is in (101, y2), I would find the difference between y2 and y1. If y2 - y1 is positive, this means there is a positive relationship and y is also approaching POSITIVE infinity. A negative relation means that it is approaching NEGATIVE infinity. However, it could be approaching a single number like "4" for instance, and you just need to plug in the right number of data sets to make that educated guess.

Formula Example:
5 + 1 / (x + 1) will always approach 5 because "1 / (x + 1) will approach 0".

Hope this helps.

5 0

3 years ago

A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$