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elena-s [515]
3 years ago
13

10. The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

A. 3

Step-by-step explanation:

Let the integers be

x

(x+1)

(x+2)

(x+3)

Sum the integers

We have,

x+(x+1)+(x+2)+(x+3)=18

x+x+1+x+2+x+3=18

4x+6=18

Subtract 6 from both sides

4x-6=18-6

4x=12

Divide both sides by 4

4x/4=12/4

x=3

The smallest integer which is x is equal to 3

Check:

3+4+5+6=18

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a + b ≥ 30,  b ≥ a + 10, the system of inequalities could represent the values of a and b

option A

<u>Step-by-step explanation:</u>

Here we have , The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greater integer, We need to find which system of inequalities could represent the values of a and b . Let's find out:

Let two numbers be a and b where b>a . Now ,

  • The sum of two positive integers, a and b, is at least 30

According to the given statement we have following inequality :

⇒ a+b\geq 30

  • The difference of the two integers is at least 10

According to the given statement we have following inequality :

⇒ b-a\geq 10

⇒ b-a+a\geq 10 +a

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Therefore , Correct option is A) a + b ≥ 30,  b ≥ a + 10

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Answer:

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Step-by-step explanation:

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R = 2.5 %

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S.I. = \frac{P (2.5)(5)}{100}

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We know hat total amount is given by

Total amount = principal amount + simple interest

A = x + S.I.

A = x + \frac{x}{8}

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Given that the total amount after 5 years is = $ 20000

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