Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
The perimeter is 10.3. I think that's already in significant digits, but I'm not sure. We just got finished learning that in chemistry and it confused me to death!
The first and the third option are correct. if you fail to do the second and last they will take away your house lol
Answer:
2094.5 muffins
Step-by-step explanation:
The problem is a little bit messy, but i’m guessing you meant that the elf ate 35% of the muffins, which 35% is 710 muffins. so since 35% of muffins is 710 muffins, let’s multiply that by 2 so we can get 70%.
so 710 x 2 is 1420. so 70% of the muffins is 1420 muffins! sadly that’s not all of the muffins. we’re still missing another 30%. since we don’t know how many muffins are in 30%, let’s just take 710 muffins - 5%. when you do that you get 674.5. so now that we know how much is in 30%, let’s take 1420 + 674.5. when you do that you get 2094.5! so you started off with 2094 and a half muffins!
