Answer:
Transportation
Explanation:
They can transport substances / nutrients from roots to different parts of the plant which makes the stem important for the plant.
You must pack food that has high concentrations of fat and protein. Food like granola bars and canned meat are a good source of energy and heat. This is because the body breaks this food down easily converting it into usable energy. Though some people would suggest that you pack food that are high in carbohydrates, fats and proteins are long-term sources of energy that you would need for your hiking trip.
Answer:
A mixture is made when two or more substances are combined, but they are not combined chemically. There are two main categories of mixtures: homogeneous mixtures and heterogeneous mixtures. In a homogenous mixture all the substances are evenly distributed throughout the mixture (salt water, air, blood).
Answer:
The receptors in the aortic and carotid bodies are chemoreceptors.
Explanation:
Chemoreceptors are specialized cells that are responsible for detecting and converting chemical signals into biological signals, to relay that information to the brain, where they will finally be interpreted. Among them we find the peripheral chemoreceptors, which are the aortic bodies, located along the wall of the aortic arch and innervated by the vagus nerve, and the carotid bodies, located in the neck. . Carotid bodies are stimulated by variations in the concentration of oxygen and carbon dioxide in the blood, as well as variations in blood pH. When the pH decreases the CO2 increases and the oxygen decreases, they activate the chemoreceptors to increase breathing.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
