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riadik2000 [5.3K]
3 years ago
8

Write an equation in standard form that is parallel to the line y = 2x - 1 that passes through the point (1, 2). 2x - y = 0 O x

- 2y = 1 0 + -2x + y = 0 O x + y =3​

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Answer:

2x - y = 0

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x - 1 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes, thus

y = 2x + c ← is the partial equation

To find c substitute (1, 2) into the partial equation

2 = 2 + c ⇒ c = 2 - 2 = 0

y = 2x ← equation in slope- intercept form

Subtract y from both sides

0 = 2x - y , that is

2x - y = 0 ← equation in standard form

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denis-greek [22]

Answer:

c. 441ft^2

Step-by-step explanation:

Area is height times length and since it's a square, safe to say that the sides are equal in length. So square root both of the given areas of the 2 square:

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8 0
3 years ago
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Black_prince [1.1K]

Answer:

x = - 2, x = 3

Step-by-step explanation:

Given

x² - x - 6 = 0

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are + 2 and - 3 , since

2 × - 3 = - 6 and 2 - 3 = - 1 , then

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Equate each factor to zero and solve for x

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x - 3 = 0 ⇒ x = 3

8 0
3 years ago
Read 2 more answers
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