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BartSMP [9]
3 years ago
5

Find the midpoint of the segment with the given endpoints. (-7,10) and (6.-10)

Mathematics
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

c

Step-by-step explanation:

cc

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Please please help me with the answer I can't do this by myself
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She bought 8 bags of candy since 10 multiplied by eight is 80 and 8 is two less than ten.(ten candies in each bag)

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4 years ago
2st2-s2 for s=3 t=6 what the answer
Ainat [17]

Answer:

3

Step-by-step explanation:

4 -1 = 3

8 0
3 years ago
the sugar-sweet company is going to transport its sugar in to Market it will cost $6,500 to rent trucks plus $150 for each ton o
Inessa05 [86]

Answer:

$ 3750  = truck rental;   $125 per ton of sugar transported

C is cost;  S is number of tons transported

Equation relating C to S would be a linear equation like y = mx + b

C = 125S + $3750

This equation would be graphed in the first quadrant only

you would start with your y-intercept at (0, 3750)

As x increases by 1, your y increases by 125 yielding these points:

(1, 3875)  (2, 4000)  (3, 4125)  etc.  

This shows that for each increase by one ton of sugar, the cost goes up $125

Step-by-step explanation:

3 0
3 years ago
Simplify:<br> 3x (x^2 + 5x – 4)
AfilCa [17]

The answer is 3x^3+15x^2-12x.

5 0
3 years ago
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
3 years ago
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