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3 years ago

16 is 20% of what number?

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

20% × ? = 16

? =

16 ÷ 20% =

16 ÷ (20 ÷ 100) =

(100 × 16) ÷ 20 =

1,600 ÷ 20 =

80;

ehidna [41]3 years ago

4 0

Answer:

Step-by-step explanation:

80 * 20% = 16

then 16 is 20% of 80

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What fractions are equivalent to 6/15

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books off the edge.

krok68 [10]

Answer:

Josh's book lands first
Ben's lands about 0.648 seconds later

Step-by-step explanation:

Using the given equation for v=60 and s=40, the height of Ben's book is ...

h(t) = -16t² +60t +40

We want to find t when h(t) = 0, so we're looking for the solution to ....

0 = -16t² +60t +40

Using the quadratic formula, we find the positive value of t to be ...

t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277

Similarly, the height of Josh's book is ...

0 = -16t² +48t +40

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The time before Josh's book lands is shorter by ...

4.3277 -3.6794 ≈ 0.6482 . . . . . seconds

Josh's book reaches the ground first, by about 0.648 seconds.

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PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the

drek231 [11]

Answer:

1) The height of the ball from 0 to 5 seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

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3 years ago