Answer:
57.72 in^2
Step-by-step explanation:
Question 1. Shapes are triangle, semi-circle, and rectangle.
Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.
Question 3.
Rectangle's area:<u>48 in^2</u>
Triangles area:8*4/2= <u>16 in^2</u>
Circle Area: pi*r^2/2(since its a semi-circle)
3.14*2^2=3.14*4=12.56/2=<u>6.28 in^2</u>
Question 4.
16-6.28=9.72
9.72+48=57.72 in^2
Answer:
$24.84
Step-by-step explanation:
i did the work lol
give brainliest please
Answer:
4.1 billion
Step-by-step explanation:
1 ft = 30.48 cm
1 in = 2.54 cm
The volume of rain that fell on the roof is given by ...
V = LWH
V = (175 ft × 30.48 cm/ft)(45 ft × 30.48 cm/ft)(11 in × 2.54 cm/in)
= 175×45×11×30.48²×2.54 cm³ = 204,412,236.336 cm³
At 20 drops per cm³, this will be ...
20×204,412,236.336 ≈ 4,088,244,727 . . . . raindrops
About 4.1 billion raindrops fell on your roof.
Answer:
Binomial
There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Step-by-step explanation:
For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem
Of the 20 copies, 2 are defective, so
.
What is the probability that you will encounter neither of the defective copies among the 10 you examine?
This is P(X = 0) when
.


There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.