Answer:
The range is y≥0
Step-by-step explanation:
The shape of this graph is a parabola
You may see this by using the Desmos calculator and typing y=x^2 if you would like to visualize.
(a) The function y = x^2 simply takes whatever number you feed it (x) and outputs x squared.
For example 
y = (2)^2=4
y = (3)^2 = 9
(b) To graph x^2 simply make a table of values and plug in 0 -> however high you would like to go ( usually to 5 or so is fine but you could go to infinity).
Example
       y = x^2
                  Y    |     X
                 ________
                  2      |   4  
                  3     |   9
                  4    |    16
In this case the function's range is y≥0 because all y values will be greater than or equal to 0. 
If you are wanting to learn how to specifically graph this you can look up (Graphing y = x²) if my quick graphing explanation back at mark (b) does not help.
 
        
             
        
        
        
This is a part:part ratio. to solve it we need to convert it into a part:whole ratio. we do this by adding the parts. the ratio of pumpkin cans to total cans is 5:7. 140/7=20. 20x5=100. 20x2=40. The answer is B. 40 cans.
        
             
        
        
        
Answer:
AC = 7
Step-by-step explanation:
1. Draw out the line and label everything you know.
2. By observation, we know that AD is also equal to AC + CD.
3. To find CD, take the length of BD (12) and subtract it by the length of BC (4): 12 - 4 = 8. The length of CD is 8.
4. Finally, to find AC, subtract the length of CD (8) from AD (15): 15 - 8 = 7. The length of AC is 7.
 
        
                    
             
        
        
        
I do believe the correct and is 9 inches 
        
                    
             
        
        
        
Answer: I can only help you with number Im sorry 
Step-by-step explanation: 
10(-1.2 + 6) = 48 
X = 3    Y = 2 
-4 x 3 = -12    30 x 2 = 60 
-12 + 60 
48  
48 = 48 
Im in middle school so Im sorry that it took me long to reply I had a hard time finding the answer. The other questions I haven’t been taught yet so maybe search up what the question is about for help if you don’t get any helpful replies :)(: