we have

This is a vertical parabola open upward
The axis of symmetry is equal to the x-coordinate of the vertex
The vertex is the point (h,k)
the equation of the axis of symmetry is 
In this problem

so the x-coordinate of the vertex is 
<u>Convert the quadratic equation in vertex form</u>
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares


remember that

so



substitute in the equation


therefore
<u>the answer is</u>

Answer:
Step-by-step explanation:
AB is a midsegment.
<u>Property of the midsegment is midsegment is half the length of the parallel side of the triangle:</u>
<u>And</u>
It is the same as 1/7*1/6. So the answer is 1/42
Answer:
26
Step-by-step explanation:
here,
the lower angle when sumed,
it is like: 154+a=180 (let angle be a) being supplementary angle sum is 180
so value of a becomes 26
then,
the above angle x is corresponding to angle a (a=x)
So value x is 26
The line we are searching for has the same slope because both lines are parallel.
The given equation y = 2x + 8 has a slope of 2.
We need the point-slope formula, the slope 2 andbthe given point.
y - y1 = m(x - x1)
y - 2 = 2(x -(-3))
y - 2 = 2(x + 3)
y - 2 = 2x + 6
We now solve for y.
y = 2x + 6 + 2
The equation we want is y = 2x + 8.