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3 years ago

Which one is it? Free p0ints! 3 PART Question!!

Mathematics

1 answer:

m_a_m_a [10]3 years ago

6 0

Answer:A,B,C

Step-by-step explanation:

Trust

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In ARST, S = 810 cm, ZT=9° and ZR=62º. Find the area of ARST, to the nearest 10th

irga5000 [103]

Answer:

47,922.3

Step-by-step explanation:

3 0

3 years ago

The answer to a division problem is given below. Label each part of the division problem

balandron [24]

Answer:

The quotient is (x² + 2x - 2)

The dividend is (2x³ + 7x² + 2x + 9)

The remainder is 15

The divisor is (2x + 3)

Step-by-step explanation:

The quotient is the answer of the division
The dividend is the part before (above) the division sign (bar of the fraction)
The divisor is the part after (below) the division sign (bar of the fraction)
The remainder is the part left over in a division problem

The relation between them is dividend ÷ divisor = quotient + $\frac{remainder}{divisor}$

Ex: 37 ÷ 5 = 7 + $\frac{2}{5}$ , where 37 is the dividend, 5 is the divisor, 7 is the quotient and 2 is the remainder

Let us solve the problem

∵ $\frac{2x^{3}+7x^{2}+2x+9}{2x+3}=x^{2}+2x-2+\frac{15}{2x+3}$

∵ dividend ÷ divisor = quotient + $\frac{remainder}{divisor}$

- Compare the rule by the given problem

∴ The quotient is (x² + 2x - 2)

∴ The dividend is (2x³ + 7x² + 2x + 9)

∴ The remainder is 15

∴ The divisor is (2x + 3)

7 0

3 years ago

Sequences and series

Vinvika [58]

Answer:

Step-by-step explanation:

$a_{n}=\frac{(n+3)!}{(n+3}=\frac{(n+3)(n+2)!}{n+3}=(n+2)!\\a_{1}=(1+2)!=3!=3*2*1=6\\a_{2}=(2+2)!=4!=4*3*2*1=24\\a_{3}=(3+2)=5!=5*4!=5*24=120\\a_{4}=(4=2)!=6!=6*5!=120*6=720\\a_{5}=(5+2)=7!=7*6!=720*7=5040$

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3 years ago

Hakim needs to simplify the expression below.

olya-2409 [2.1K]

Answer:

<h2><u><em>B. SUBTRACTION</em></u></h2>

Step-by-step explanation:

We solve these problems by doing PEMDAS.

Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

As you can see, 1.85 - 0.3 is in parentheses, so we will do that first.

8 0

3 years ago

Read 2 more answers

How many different ways can a teacher select 3 students from a class of 15 students to each perform a different classroom task?

Yuliya22 [10]

Answer: 455ways

Step-by-step explanation:

This can be done according to rule of combination because it talks about selection.

In order to select r object from a pool of n objects, it is represented as nCr = n!/(n-r)!r!

Therefore to select 3 students from a class of 15students, this will give us 15C3.

15C3 = 15!/(15-3)!3!

= 15!/12!3!

= 15×14×13×12!/12!×6

= 15×14×13/6

= 455ways

This selection can be done in 455ways

5 0

3 years ago