What is the distance between (7,-2) and (3,1)

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

Answer:

Distance = 5

Step-by-step explanation:

x2 = 3

y2 = 1

x1 = 7

y1 = -2

=> d = Square root of (3 - 7)^2 + (1 + 2)^2

=> d = Square root of (-4)^2 + (3)^2

=> d = Square root of 16 + 9

= d = Square root of 25

d = 5

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