Answer:
(a)The current passes through the solenoid is 11.7 A.
(b) The new current will be one-fourth of the initial current.
Explanation:
Given that,
The number of turns per meter = 385
Diameter of solenoid = 17.0 cm = m
Magnetic flux through core of solenoid = Tm²
(a)
Magnetic field B=
T/amp m
Cross section area of the solenoid A=
m²
The angle between magnetic field and cross section of the solenoid is
The magnetic flux through a area A with magnetic fie;d B is
=11.7 A
The current of the solenoid is 11.7 A.
(b)
From the above equation it is clear that, the current is inversely proportional to the square of the diameter of a solenoid.
.
Consider d' be the new diameter of the solenoid .
Since the new diameter of the solenoid is double of the initial diameter.
That is d'= 2d.
⇒I=4I'
The new current will be one-fourth of the initial current.