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4 years ago

When did they start using the word "Scrubbed" for launches?

Physics

1 answer:

VladimirAG [237]4 years ago

6 0

Answer:

Many speculation exists for why the term 'scrubbed' is used in relation to launches. One of these is that during world war II, when the Air force planned bombing raids. These Air force missions had their briefings done with illustration of the details of the launch and and flight drawn on chalkboards. When some of mission flight takeoffs were canceled (due to bad weather or a malfunction or other reasons) the details were then scrubbed off of the chalkboard. This idea of the mission being scrubbed meaning that it is no longer to be followed through with, proceeded to this modern day rocket and aviation launches.

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neonofarm [45]

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3 years ago

You see a lightning bolt flash in the distant sky. You hear the corresponding thunder 6.8 seconds later. If the temperature is 2

Anna35 [415]

Answer:

$Distance = 2.4\ km$

Explanation:

Given

$Time (t) = 6.8s$

$Temperature = 28C$

Required

Determine the distance at which the lighting struck

First, we need to determine the speed at which the lighting struck because the peed of sound varies with temperature.

At about 28C, the speed of sound is 346m/s

So, we have the following:

$Speed = 346m/s$

$Time = 6.8s$

Distance is calculated as thus:

$Distance = Speed * Time$

$Distance = 346m/s * 6.8s$

$Distance = 2352.8$

Divide by 1000 to get distance equivalent in kilometers

$Distance = \frac{2352.8km}{1000}$

$Distance = 2.3528km$

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7 0

3 years ago

A cubical furnace with external dimensions of 0:6 m is constructed from reclay brick. If the wall thickness is 40 mm, the inner

Alja [10]

Answer:

Explanation:

surface area of furnace = 6 x .6²

=2.16 m²

Rate of heat loss = k A ( θ₂ -θ₁ ) / t where k is coefficient of thermal conductivity , A is surface involved , θ₂ -θ₁ is temperature difference and t is thickness .

For fire clay thermal conductivity

= .05 W / m . K

.05 x 2.16 x ( 630 - 70 ) / .04

= 1512 W

= 1.5 kW .

8 0

3 years ago

Compare and contrast fossil fuels and biofuels

enot [183]

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5 0

3 years ago

An office window has dimensions 3.5 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.96 at

Nina [5.8K]

Answer:

Force=29789.55 N

Explanation:

Given data

dimension=3.5m by 2.1m

P(outside pressure)=0.96 atm

P(inside pressure)=1.00 atm

Force=?

Solution

Area=L×W

A=(3.5)×(2.1)

$A=7.35m^{2}$

As we know

F=PA

For P(pressure)

P=P(inside)-P(outside)

P=1.00-0.96

P=0.04 atm

convert atm to pascal (pa) we get

P=4053 pa

F=PA

F=(4053)×(7.35)

F=29789.55 N

8 0

3 years ago