Question

2. A loop of wire of area 0.7 m is moving into a 0.9 T magnetic field. If it takes 5

Answer 1

Answer:

fem = -0.126 V

Explanation:

Faraday's law is

          fem =  $- \frac{d \phi}{dt}$

where the flow is

          Ф = B . A = B A cos θ

bold letters indicate vectors.

In this case, the normal to the area is parallel to the magnetic field, so the angle is zero and the cos0 = 1

           fem = $- A \ \frac{dB}{dt}$

in this case they indicate that to carry the loop from outside to inside the field in Δt = 5 s, so we can change them by variations

           fem = $- A \frac{\Delta B}{\Delta t}$

let's calculate

           fem = - 0.7 (0.9 -0) / 5

           fem = -0.126 V