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olga nikolaevna [1]
3 years ago
7

Are the ratios 6:4 and 19:12 equivalent?

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Answer: No, they are not.

Step-by-step explanation: To see if ratios are equivalent, you have to simplify them. 6:4 can be simplified to 3:2 but 19:12 cannot be simplified anymore. Since 3:2 is not equal to 19:12, they are not equivalent.

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So let’s imagine this on a number line…so we know that the fish starts at -17 1/3 on the number line but he dives (that means go lower in our number line) 6 1/2 feet downward so let’s set up an equation:

-17 1/3 - 6 1/2
Now, let’s subtract the two integers by finding the least common denominator of 2 and 3 so it can be easier to solve in this case it’s 6…then let’s set up our new equation:

-17 2/6 - 6 3/6
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6 0
2 years ago
Type an equation for the following pattern
umka2103 [35]

For the given table, the difference between two consecutive y terms are

4-3=5-4=6-5=7-6=1

It means the difference is constant. So the given function is in arithmetic progression.

And to find the equation, representing the given series, we will use the formula for the nth term of arithmetic series, which is

a_{n}= a+ (n-1)d

Here,

a_{n} =y, n=x, and \ d  \ for \  the \  common \ difference.

So we will get

y= 3+(x-1)(1)
\\
y = 3 + x-1
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y= x +2

4 0
3 years ago
Does the set of ordered pairs {(5,13), (6,12), (7,11) (9,9) (10,11)} define a function?
Tcecarenko [31]
The answer is B: Yes because each input has only one output
4 0
3 years ago
Read 2 more answers
Which statement is true about angles 3 and 6
vlada-n [284]

Answer:

They are vertical angles.

Step-by-step explanation:

8 0
4 years ago
Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x
zvonat [6]

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

can be wrtten as:

\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

5 0
1 year ago
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