4(3B + 2) -7Bplease help!!
2 answers:
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The derivative, f'(x) = 6x^2+1, is never negative, so f(x) is monotonic, hence invertible.
f'(-2) = 6(-2)²+1 = 25
If point (-2, -26) is on the graph of function f(x), and the slope is 25 there, then (-26, -2) is on the graph of f⁻¹(x), and the slope is 1/25 there. The equation of the tangent line throught that point can be written in point-slope form as
... y +2 = (1/25)(x +26)
Answer:
-1/5
Step-by-step explanation:
slope can be found with the equation found in the image.
assign each coordinate with the according variable
x1 = 3 x2 = -7 y1 = 2 y2 = 4
and input the values accordingly.
4 - 2 / -7 - 3 PEMDAS (order of operations)
= 2/ -10 Simplify
= 1/ -5
=-1/5
