
Let,
- Mass of the steel be 108x
- Mass of the copper be 7x
- Then, Total mass = 108x + 7x = 115x
Given,
- Total mass of the coin = 230 mg
That means,
⇛ Total mass of the coin = 230 mg
⇛ 115x = 230 mg
⇛ x = 230 mg/115
⇛ x = 2 mg
Then,
- Mass of the steel = 108(2) = 216 mg
- Mass of the copper = 7(2) = 14 mg
☁️ ANSWER - 14 mg (Mass of copper)
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer:
14, 48, 50
Step-by-step explanation:
To check which set of side length can be used to form a right triangle we use pythagorean theorem
c^2 = a^2 + b^2
biggest side (hypotenuse is c^2)
(a) 14, 48, 50

2500= 196+2304
2500= 2500 that is true
(b) 30, 40, 60

3600= 900+ 1600
3600= 2500 that is false
(c) 14, 50, 60

3600= 196+2500
2500= 2196 that is false
(d) 10, 24,28

784=100+576
784=676 that is false
Answer:
You want to maximize x and minimize y
Maximum y = 8
Minimum y = 10
8-10= -2
Answer:
x>2 or x<-10
Step-by-step explanation:
9|x +4|>54
Divide each side by 9
9/9|x +4|>54/9
|x +4|>6
There are two solutions, one positive and one negative
x+4 >6 or x+4 < -6
Subtract 4 from each side
x+4-4 >6-4 or x+4-4 < -6-4
x>2 or x<-10
89kg in stones would be 12.598 stones