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astra-53 [7]
4 years ago
13

Suppose z varies directly with x and inversely with the

Mathematics
1 answer:
bija089 [108]4 years ago
5 0

Answer:

K = 27

z = 1.89

Step-by-step explanation:

Check attachment below

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F(x) = 4x - 1<br> g(x) = x2 - 4x<br> Find f(g(3))
nasty-shy [4]

Answer:

-13

Step-by-step explanation:

hello,

Replace x by the value as below

g(3)=3^2-4\times3=9-12=-3\\f(g(3))=f(-3)=4\times(-3)-1=-12-1=-13\\

Thanks

5 0
3 years ago
Simplify 2 to the 5 power to the fourth power over 3 to the second power
melisa1 [442]
I'm assuming you mean 2^(5)(4/3)(2). 
So multiplying all of the powers together yields 2^(40/3)
4 0
3 years ago
BONUS 1. We have 5 Blue balls. + Red balls, and 3 Green balls. Find the probability that the ball that we pick is either a Red b
Ivanshal [37]

Answer:

8/13

Step-by-step explanation:

5 + 5 + 3 = 13 total

5 red balls + 3 green balls = 8

4 0
3 years ago
Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n
Nady [450]

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

The maclaurin series for f(x) is defined by the following formula:

f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}--------------(1)

Where f^{i} is the i - th derivative of the function

If f(x) = e^{-6x}, then the formula of the i - th derivative of the function is:

f^{i} =(-6)^{i} .e^{-6x}----------------------(2)

Then,

f^{i}(0) = (-6)^{i}

Lastly, the equation of the trascendental function by Maclaurin series is: f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i}  }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}---------------(3)

Hence,

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

Find out more information about maclaurin series here

brainly.com/question/24179531

#SPJ4

4 0
1 year ago
3 PART QUESTION!
Illusion [34]

Answer:

See below

Step-by-step explanation:

<u>Given relationship:</u>

  • d = rt

a) r = 3, d = 4

  • t = d/r = 4/3 h = 1 h 20 min

b) d = 4 miles, rate = r

  • t = 4/r, domain is r and must be greater than zero

c) d = 4 miles, time = t

  • r = d/t = 4/t, domain is t and it must be greater than zero

d) t = 3 h, rate = r

  • d = rt = 3r, domain is r and can be anything greater than zero
5 0
3 years ago
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