Answer:
[-5, 4) ∪ (4, ∞)
Step-by-step explanation:
Given functions:


Composite function:
![\begin{aligned}(f\:o\:g)(x)&=f[g(x)]\\ & =\dfrac{1}{\sqrt{x+5}-3} \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%5C%3Ao%5C%3Ag%29%28x%29%26%3Df%5Bg%28x%29%5D%5C%5C%20%26%20%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7Bx%2B5%7D-3%7D%20%5Cend%7Baligned%7D)
Domain: input values (x-values)
For
to be defined:


Therefore,
and 
⇒ [-5, 4) ∪ (4, ∞)
5 x 3 = 15
Ty spent $15 on binders
Answer:
If
is divisible by 3, the n is also divisible by 3.
Step-by-step explanation:
We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then,
is not divisible by 3.
Let n not be divisible by 3. Then
can be written in the form of fraction
, where x and y are co-prime to each other or in other words the fraction is in lowest form.
Now, squaring

Thus,


It can be clearly seen that the fraction
is in lowest form.
Hence,
is not divisible by 3.
Thus, by contrapositivity if
is divisible by 3, the n is also divisible by 3.
Answer:
-15
Step-by-step explanation:
<u>Definition of absolute value: </u>
<em>Distance from zero on a number line. </em>
<em />
Imagine a number line with 0 in the middle of it. Now mark the number 3 on it. Also mark the <em>opposite </em>of 3, which is -3. What is the <u>distance</u> from zero to those 2 points? it's 3.
This is exactly like saying |3| = 3 and |-3| = 3
Even if the number inside absolute value is negative, it <em><u>simplifies</u></em> to the positive of the same number.
_______________________________
So let's talk about your problem.
-|-15|
> the absolute value simplifies to 15
-|-15| = - 15
So that ends up being your answer.

Hope this helps!!!!!!!