Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
Answer:
1. -9xy
2. 6ab
3.-8mn
4. 17nx
Step-by-step explanation:
Answer:
(-2 , 2)
Step-by-step explanation:
A(-8 , 2) = (x1 , y1)
B(4 , -2) = (x2 , y2)
midpoint = (x1 + x2/2 , y1 + y2/2)
=(-8 + 4/2 , 2-(-2)/2)
=(-4/2 , 2+2/2)
(-2 , 2)
(3 , 7) = (x1 , y1)
(9 , 2) = (x2 , y2)
distance of PQ = 
=
=
=
=
=7.8 unit