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eduard
3 years ago
15

Write 2603094 using exponents?

Mathematics
2 answers:
Artemon [7]3 years ago
7 0
2*10^6 + 6*10^5 + 3*10^3 +9*10^1 +4*10^0

see expanded form is adding the digits together. and it would be what ever one number is times 10 to the power of how many digits are after that number. you skip the 0's though. hope this helps
netineya [11]3 years ago
7 0
<span>2603090+<span>4
</span></span>
2603090+(4)(1)
2603090+4(10^{0})
<span>2603000+90+<span>4(</span></span><span>10^{0})
</span><span><span>2603000+<span><span>(9)</span><span>(10)</span></span></span>+4</span>(<span>10^{0})
</span>
2603000+9(<span>10^{1})+4</span>(<span>10^{1})
</span>
2600000+3000+9<span><span>(10^{1})</span>+4</span>(<span>10^{0})

</span>
<span><span>2600000+<span><span>(3)</span><span>(1000)</span></span></span>+9</span><span>(10^{1})+4</span>(<span>10^{0})
</span>
2600000+3(10^{3})+9(10^{1})+4(<span>10^{0})

</span>
2000000+600000+3<span><span>(10^{3})</span>+9</span><span>(10^{1})+4</span>(<span>10^{0})

</span>
<span><span>2000000+<span><span>(6)</span><span>(100000)</span></span></span>+3</span><span>(10^{3})+9</span>(10^{1})+4(<span>10^{0})

</span>
2000000+6<span><span>(10^{5})</span>+3</span><span><span>(10^{3})</span>+9</span>(10^{1})+4(<span>10^{0})

</span>
<span><span>(2)<span>(1000000)</span></span>+6</span><span>(10^{5})+3</span><span>(10^{3})+9</span>(10^{1})+4(<span>10^{0})

So your final answer would be </span>
2<span><span>(10^{6})</span>+6</span><span>(10^{5})+3</span>(10^{3})+9(10^{1})+4(<span>10^{0})
</span>





















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