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In-s [12.5K]
3 years ago
9

Determine the solution set for (x-3)2-18=-4

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
Add 18 to both sides to get 2(x-3)=14, then divide by 2 to get (x-3)=7, and finally add 3 to both sides to get x=10, hope that helps :)
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I need help I’m bad at math
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The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
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3 years ago
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Sergeeva-Olga [200]

Answer:

b.  area = 18 square units

Step-by-step explanation:

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3 0
3 years ago
The class average on a math test was an 82 with a standard deviation of 5. If the 
Alex787 [66]

Answer:

Option 3 and 4.

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

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z=\frac{x-\mu}{\sigma} \\\\z=\frac{74-82}{5} =-1.6

Option 1 is incorrect

2) For x < 87

z=\frac{x-\mu}{\sigma} \\\\z=\frac{87-82}{5} =1

From the normal distribution table, P(x < 87) = P(z < 1) = 0.8413 = 84.13%

Option 2 is incorrect

3) For x = 95:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{95-82}{5} =2.6

Option 3 is correct

4) For x < 77

z=\frac{x-\mu}{\sigma} \\\\z=\frac{77-82}{5} =-1

From the normal distribution table, P(x < 77) = P(z < -1) = 0.16 = 16%

Option 4 is correct

5) For x > 92

z=\frac{x-\mu}{\sigma} \\\\z=\frac{92-82}{5} =2

From the normal distribution table, P(x > 92) = P(z > 2) = 1 - P(z < -2) = 1 - 0.9772 = 0.0228 = 2.28%

Option 5 is incorrect

8 0
3 years ago
Find the sum of the first six terms of the sequence for which a2=0.7 and a3=0.49.
alina1380 [7]
A1 = 0.91
a6 = -0.14
sum = (0.91+-0.14) /2
sum = 2.31
8 0
3 years ago
Read 2 more answers
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