The instructions that he microprocessor can execute each
second if the assembly line is present will be depending on the workload and
the architecture’s core because it is all depending on the speed of the CPU and
the multiplier that it acquires.
Follow these steps.
1. Make sure that your pc is on.
2. Press your Window key - on your bottom left of your keyboard you will see a window key.
3. After pressing it will show a tab on your bottom left of your monitor.
4. On that tab you will see an (All Programs) text.
5. Click it and it will show all programs available on your pc.
Answer:
24
Explanation:
11000 is equivalent to 24 because if you look at a flippy do, the base is 2. so going from right-left, 2^0 is 1 for the first 0. second zero would be 2^1 which is 2. then the third zero is 4 (2^2). since they are zero’s, they are turned off, but the 1’s indicate that those bases are turned on. the first one going from right to left would then be 8 (2^3) and the last 1 going from right-left is 16 (2^4). so 16+8=24!
edit: didn’t mean to rate myself 1 star lol
Answer: Dereferencing a variable that is not a pointer
Explanation:
The execution time also refered to as the CPU time pertaining to a given task is the time that is used by the system to execute a task.
Some of the reasons for a fatal execution-time error include:
• Dereferencing a pointer that has not been initialized properly
• Dereferencing a null pointer
• Dereferencing a pointer that has not been assigned to point to a specific address.
It should be noted that dereferencing a variable that is not a pointer doesn't cause a fatal execution-time error.
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
