D is the mode in witch only or mostly text is visible.<span />
Answer:
Option (B) i.e., Certificate authority is the correct option to the following question.
Explanation:
The following option is correct because it an organization or company who validating the identification of that object that exists and it also verifies the information of the third party.
Option A is incorrect because it is the tool or software that protects the system from the outsiders or the malware.
Option b is incorrect because Online certificate is issued for any software or application or the certification in the field of study.
Answer:
Answer explained below
Explanation:
I have given two approaches in implementing the solution.
1. Using the for loop, in which you have to iterate over all the elements in list 1 and check in list 2
2. Use the set intersection method. As intersection will give u the common elements. And we can get there length by using len method.
I have added the code along with the snapshot and inline comment for the ease of you to understand. Please check the methods below. You can use either of them.
METHOD-1:
********** CODE *****************
def matches(tickets,winner):
tickets = set(tickets)
winner = set(winner)
counter = 0 #To Count the common elements
for i in tickets: # Iterate over all the elements in tickets.
if i in winner: # Check the element in the winner list
counter = counter+1
return counter
METHOD -2:
********** CODE ********************
def matches(tickets, winner):
tickets = set(tickets)
winner = set(winner)
return len(tickets.intersection(winner))
The answer is B: Spelling and Grammar
Nick knows that it is important to check for spelling and grammar mistakes before distributing his content. Fortunately, Microsoft Word makes it easier to spell check his work all at once by running the spelling and grammar checker. To do this on his Word document, he is required to click the Review tab and then click the Spelling or Spelling & Grammar button. If Word finds any mistakes, a dialog box will pop up with an option to correct.
The right code is,
secondWord = sentence.substr (sentence.find ("`") + 1);
secondWord = secondWord.substr (0, secondWord.find ("`"));
