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4 years ago

Help solve mathematics question, please. Photo.

Mathematics

1 answer:

cricket20 [7]4 years ago

3 0

Hi Mark

3x+y=4

2x+y=5

Solve 3x+y=4 for y

Add -3x to both sides

3x+y-3x=4-3x

y=-3x+4

Substitute -3x+4 for y in 2x+y=5

2x+y=5

2x-3x+4=5

Simplify both sides of the equation

-x+4=5

Add -4 to both sides

-x+4-4=5-4

-x=1

Divide both sides by -1

-x/-1= 1/-1

x=-1

Substitute -1 for x in y=-3x+4

y=-3x+4

y=(-3)(-1)+4

Simplify both sides of the equation

y=7

Answer: (-1,7)

I hope that's help ! Have a great weekend :)

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Option A: $(x+3)^2+(y+2)^2=4$ is the equation of the circle

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The equation of the circle is $x^{2} +y^2+6x+4y+10=1$

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Let us subtract 10 from both sides of the equation.

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Now, we shall complete the square, let us add and subtract the equation by 9 to write the term $\left(x^{2}+6 x\right)$ in the form of $(a+b)^2$

Thus, we have,

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Simplifying, we get,

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Similarly, we shall complete the square for the term $\left(y^{2}+4 y\right)$ in the form of $(a+b)^2$

Thus, we have,

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Oduvanchick [21]

Their is no picture

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4 years ago

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